Difference between revisions of "2023 AMC 10B Problems/Problem 20"
Technodoggo (talk | contribs) |
Technodoggo (talk | contribs) (→Solution 1) |
||
| Line 1: | Line 1: | ||
| + | ==Problem 20== | ||
| + | Four congruent semicircles are drawn on the surface of a sphere with radius 2, as | ||
| + | shown, creating a close curve that divides the surface into two congruent regions. | ||
| + | The length of the curve is <math>\pi\sqrt{n}</math>. What is 𝑛? | ||
| + | |||
==Solution 1== | ==Solution 1== | ||
Revision as of 16:01, 15 November 2023
Problem 20
Four congruent semicircles are drawn on the surface of a sphere with radius 2, as
shown, creating a close curve that divides the surface into two congruent regions.
The length of the curve is 
. What is 𝑛?
Solution 1
There are four marked points on the diagram; let us examine the top two points and call them 
and 
. Similarly, let the bottom two dots be 
and 
, as shown:
![[asy] import graph; import geometry; unitsize(1cm); pair A = (-1.41, 1.41); pair B = (1.41, 1.41); pair C = (1.41, -1.41); pair D = (-1.41, -1.41); pair O = (0, 0); draw(circle(O,2)); draw(A--O--B,black+dashed); draw(C--O--D,black+dashed); dot(A);dot(B);dot(C);dot(D);dot(O); label("$A$", A, NW); label("$B$", B, NE); label("$C$", C, SE); label("$D$", D, SW); label("$O$", (0,0.1), N); [/asy]](http://latex.artofproblemsolving.com/0/e/2/0e2436e052e566b8c2cfb41c5674fc19c3e7ece2.png)
This is a cross-section of the sphere seen from the side. We know that 
, and by Pythagorean therorem, 
Each of the four congruent semicircles has the length 
as a diameter (since is congruent to 
and 
), so its radius is 
Each one's arc length is thus 
We have 
of these, so the total length is 
, so thus our answer is 
~Technodoggo
