Difference between revisions of "2023 AMC 12A Problems/Problem 15"
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==Solution 1== | ==Solution 1== | ||
By "unfolding" line APQRS into a straight line, we get a right triangle ABS. | By "unfolding" line APQRS into a straight line, we get a right triangle ABS. | ||
| − | <cmath>cos(\theta)=120 | + | <cmath>cos(\theta)=\frac{120}{100}</cmath> |
| − | <cmath>\theta=arccos(\frac{5}{6})</cmath> | + | <cmath>\theta=\boxed{\textbf{(A) } arccos(\frac{5}{6})}</cmath> |
Revision as of 23:45, 9 November 2023
Question
[uh someone insert diagram]
Solution 1
By "unfolding" line APQRS into a straight line, we get a right triangle ABS.
![\[cos(\theta)=\frac{120}{100}\]](http://latex.artofproblemsolving.com/7/a/d/7add3a939b083adad211b0c953412e98a51b9314.png)
![\[\theta=\boxed{\textbf{(A) } arccos(\frac{5}{6})}\]](http://latex.artofproblemsolving.com/8/9/9/899f9c01aa253eb55493ffe471e4a565e4d0c356.png)
