2023 AMC 12A Problems/Problem 15

Revision as of 23:45, 9 November 2023 by Lptoggled (talk | contribs) (Solution 1)

Question

[uh someone insert diagram]

Solution 1

By "unfolding" line APQRS into a straight line, we get a right triangle ABS. \[cos(\theta)=\frac{120}{100}\] \[\theta=\boxed{\textbf{(A) } arccos(\frac{5}{6})}\]