Difference between revisions of "2023 AMC 12B Problems/Problem 12"

Revision as of 18:00, 15 November 2023

Problem

For complex number $u = a+bi$ and $v = c+di$ (where $i=\sqrt{-1}$ ), define the binary operation

$u \odot v = ac + bdi$

Suppose $z$ is a complex number such that $z\odot z = z^{2}+40$ . What is $|z|$ ?

$\textbf{(A) }2\qquad\textbf{(B) }5\qquad\textbf{(C) }\sqrt{5}\qquad\textbf{(D) }\sqrt{10}\qquad\textbf{(E) }5\sqrt{2}$

Solution 1

let $z$ = $a+bi$ . $z \odot z a^{2}+b^{2}i$ . This is equal to $z^{2} + 40 = a^{2}-b^{2}+40+2abi$ Since the real values have to be equal to each other, $a^{2}-b^{2}+40 = a^{2}$ Simple algebra shows $b^{2} = 40$ , so $b$ is $2\sqrt{10}$ . The imaginary components must also equal each other, meaning $b^{2} = 2ab$ , or $b = 2a$ . This means $a = \frac{b}{2} = \sqrt{10}$ . Thus, the magnitude of z is $\sqrt{a^{2}+b^{2}} = \sqrt{50} = 5\sqrt{2}$ $=\text{\boxed{\textbf{(E) }5\sqrt{2}}}$

~Failure.net

@@ Line 18: / Line 18: @@
 Thus, the magnitude of z is <math> \sqrt{a^{2}+b^{2}} = \sqrt{50} = 5\sqrt{2}</math>
 <math>=\text{\boxed{\textbf{(E) }5\sqrt{2}}}</math>
-~zhenghua
 ~Failure.net

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Difference between revisions of "2023 AMC 12B Problems/Problem 12"

Revision as of 18:00, 15 November 2023

Problem

Solution 1