Difference between revisions of "2023 AMC 8 Problems/Problem 10"
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| − | + | Harold made a plum pie. Lets call the total amount of this pie <math>x</math>. We can distribute into different fractions of pie that the animals ate. First Harold ate <math>\frac{1}{4} * x</math> of the pie and the remains are <math>\frac{3}{4}</math> of the pie. From this a moose comes and eats <math>\frac{3}{4} * \frac{1}{3}</math> and what remains is <math>\frac{3}{4} - \frac{1}{4} = \frac{1}{2}</math>. From this a porcupine comes and eat <math>\frac{1}{3} * \frac{1}{2} = \frac{1}{6}</math> and our final answer of what remains is <math>\frac{1}{2} - \frac{1}{6} = \boxed{\text{(D)}\frac{1}{3}}</math> | |
Revision as of 19:32, 24 January 2023
Harold made a plum pie. Lets call the total amount of this pie 
. We can distribute into different fractions of pie that the animals ate. First Harold ate 
of the pie and the remains are 
of the pie. From this a moose comes and eats 
and what remains is 
. From this a porcupine comes and eat 
and our final answer of what remains is 
