Difference between revisions of "2023 AMC 8 Problems/Problem 5"
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First we find the ratio of trout: total fish using the <math>\frac{30}{180} = \frac {1}{6}</math>then since we know there is a <math>250</math> in the numerator as there are <math>250</math> trout in the whole lake we get <math>\frac{250}{250*6} =\boxed{\text{(B)}1500}</math> fish total in the lake. | First we find the ratio of trout: total fish using the <math>\frac{30}{180} = \frac {1}{6}</math>then since we know there is a <math>250</math> in the numerator as there are <math>250</math> trout in the whole lake we get <math>\frac{250}{250*6} =\boxed{\text{(B)}1500}</math> fish total in the lake. | ||
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| + | ~apex304, SohumUttamchandani, wuwang2002, TaeKim, Cxrupptedpat | ||
Revision as of 20:23, 24 January 2023
First we find the ratio of trout: total fish using the 
then since we know there is a 
in the numerator as there are trout in the whole lake we get 
fish total in the lake.
~apex304, SohumUttamchandani, wuwang2002, TaeKim, Cxrupptedpat
