2023 AMC 8 Problems/Problem 6

The maximum possible value of using the digit $2,0,2,3$ . We can maximize our value by keeping the $3$ and $2$ together in one power. (Biggest with biggest and smallest with smallest) This shows $3^{2}*0^{2}$ = $9*1$ = $9$ . (Don't want $2^{0}$ cause that's $0$ !) It is going to be $\boxed{\text{(C)}9}$

~apex304, SohumUttamchandani, wuwang2002, TaeKim, Cxrupptedpat, stevens0209 (editing)

Page

Toolbox

Search

2023 AMC 8 Problems/Problem 6