Difference between revisions of "2023 SSMO Accuracy Round Problems/Problem 6"

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==Solution==
 
==Solution==
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By Vieta's Relation we get, <math>\sum_{cyc}{}\alpha=2023,</math> <math>\sum_{cyc}{}\alpha\beta=0</math> and <math>\prod_{cyc}{}\alpha=-2023^{2023}</math> Therefore we have to find the value of <cmath>\sum_{cyc}{}\left(\frac{\alpha^2+\beta^2}{\alpha+\beta}\right)\implies </cmath>

Revision as of 13:50, 23 December 2023

Problem

Let the roots of $P(x) = x^3 - 2023x^2 + 2023^{2023}$ be $\alpha, \beta, \gamma.$. Find \[\frac{\alpha^2 + \beta^2}{\alpha + \beta} + \frac{\beta^2 + \gamma^2}{\beta+\gamma} + \frac{\gamma^2 + \alpha^2}{\gamma + \alpha}\]

Solution

By Vieta's Relation we get, $\sum_{cyc}{}\alpha=2023,$ $\sum_{cyc}{}\alpha\beta=0$ and $\prod_{cyc}{}\alpha=-2023^{2023}$ Therefore we have to find the value of \[\sum_{cyc}{}\left(\frac{\alpha^2+\beta^2}{\alpha+\beta}\right)\implies\]