Difference between revisions of "2024 AMC 8 Problems/Problem 1"
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<math>\textbf{(A) } 0\qquad\textbf{(B) } 2\qquad\textbf{(C) } 4\qquad\textbf{(D) } 6\qquad\textbf{(E) } 8</math> | <math>\textbf{(A) } 0\qquad\textbf{(B) } 2\qquad\textbf{(C) } 4\qquad\textbf{(D) } 6\qquad\textbf{(E) } 8</math> | ||
| − | ==Solution== | + | ==Solution 1== |
| + | |||
| + | <cmath>222,222-22,222-2,222-222-22-2</cmath> | ||
| + | <cmath> \equiv 2-2-2-2-2-2</cmath> | ||
| + | <cmath> \equiv -8</cmath> | ||
| + | So the solution is <math>(E)</math> <math>8</math> | ||
Revision as of 13:59, 25 January 2024
Problem
What is the ones digit of ![\[222,222-22,222-2,222-222-22-2?\]](http://latex.artofproblemsolving.com/e/2/f/e2fbba6a2cccb3d60b70444a8b272999a204281e.png)
Solution 1
![\[222,222-22,222-2,222-222-22-2\]](http://latex.artofproblemsolving.com/a/2/7/a2725dab8150e76bea650e7fe8585ceecf400c33.png)
![\[\equiv 2-2-2-2-2-2\]](http://latex.artofproblemsolving.com/d/b/3/db37d9f234f299d75e5207584906b039abedc379.png)
![\[\equiv -8\]](http://latex.artofproblemsolving.com/2/9/d/29ddd3ce8b10dc0f9a6f36a79d1ad76b5c400abb.png)
So the solution is 
