Difference between revisions of "2024 AMC 8 Problems/Problem 7"

(Problem)
(Problem)
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A <math>3x7</math> rectangle is covered without overlap by 3 shapes of tiles: <math>2x2</math>, <math>1x4</math>, and <math>1x1</math>, shown below. What is the minimum possible number of <math>1x1 tiles used?
 
A <math>3x7</math> rectangle is covered without overlap by 3 shapes of tiles: <math>2x2</math>, <math>1x4</math>, and <math>1x1</math>, shown below. What is the minimum possible number of <math>1x1 tiles used?
  
</math>\textbf{(A) } 1\qquad\textbf{(B) } 2\qquad\textbf{(C) } 3\qquad\textbf{(D) } 4\qquad\textbf{(E) } 5<math>
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</math>\textbf{(A) } 1\qquad\textbf{(B) } 2\qquad\textbf{(C) } 3\qquad\textbf{(D) } 4\qquad\textbf{(E) } 5
  
 
==Solution 1==
 
==Solution 1==
  
We can eliminate B, C, and D, because they are not </math>21-<math>any multiple of </math>4<math>. Finally, we see that there is no way to have A, so the solution is </math>(E) \boxed{5}$.
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We can eliminate B, C, and D, because they are not <math>21-</math> any multiple of <math>4</math>. Finally, we see that there is no way to have A, so the solution is <math>(E) \boxed{5}</math>.
  
 
==Solution 1==
 
==Solution 1==

Revision as of 17:08, 25 January 2024

Problem

A $3x7$ rectangle is covered without overlap by 3 shapes of tiles: $2x2$, $1x4$, and $1x1$, shown below. What is the minimum possible number of $1x1 tiles used?$\textbf{(A) } 1\qquad\textbf{(B) } 2\qquad\textbf{(C) } 3\qquad\textbf{(D) } 4\qquad\textbf{(E) } 5

Solution 1

We can eliminate B, C, and D, because they are not $21-$ any multiple of $4$. Finally, we see that there is no way to have A, so the solution is $(E) \boxed{5}$.

Solution 1

Video Solution 1(easy to digest) by Power Solve

https://youtu.be/16YYti_pDUg?si=KjRhUdCOAx10kgiW&t=59