2024 AMC 8 Problems/Problem 8

Revision as of 16:31, 25 January 2024 by Samvitbharadwaj (talk | contribs) (Solution 1)

Problem

==Solution 1== (BRUTE FORCE) How many values could be on the first day? Only $2. The second day, you can either add 3, or double, so you can have$5, or $4. For each of these values, you have 2 values for each. For$5, you have $10 or$8, and for $4, you have$8 or $7. Now, you have 2 values for each of these. For$10, you have $13 or$20, for $8, you have$16 or 11, for 8, you have 16 or 11, and for 7, you have 14 or 10.