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Difference between revisions of "2025 AMC 8 Problems/Problem 9"

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The 2025 AMC 8 is not held yet. Please do not post false problems.
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There are <math>10</math> matchsticks on the table. Percy takes <math>1</math>, <math>2</math> or <math>3</math> matchsticks each time. How many ways are there for him to take all the matchsticks?
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<math>\textbf{(A)}\ 274 \qquad \textbf{(B)}\ 275 \qquad \textbf{(C)}\ 276 \qquad \textbf{(D)}\ 280 \qquad \textbf{(E)}\ 295</math>

Latest revision as of 09:33, 23 February 2024

There are $10$ matchsticks on the table. Percy takes $1$, $2$ or $3$ matchsticks each time. How many ways are there for him to take all the matchsticks?

$\textbf{(A)}\ 274 \qquad \textbf{(B)}\ 275 \qquad \textbf{(C)}\ 276 \qquad \textbf{(D)}\ 280 \qquad \textbf{(E)}\ 295$

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