Difference between revisions of "Aczel's Inequality"

(New page: '''Aczel's Inequality''' states that if <math>a_1^2>a_2^2+\cdots +a_n^2</math>, then <center><math>(a_1b_1-a_2b_2-\cdots -a_nb_n)^2\geq (a_1^2-a_2^2-\cdots -a_n^2)(b_1^2-b_2^2-\cdots -b_n...)
(No difference)

Revision as of 14:50, 15 September 2008

Aczel's Inequality states that if $a_1^2>a_2^2+\cdots +a_n^2$, then

$(a_1b_1-a_2b_2-\cdots -a_nb_n)^2\geq (a_1^2-a_2^2-\cdots -a_n^2)(b_1^2-b_2^2-\cdots -b_n^2).$

Proof

Template:Incomplete

See also

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