Difference between revisions of "Angle Bisector Theorem"

(removed ambiguities/added links.)
(image/stubbed)
Line 1: Line 1:
 
The '''Angle Bisector Theorem''' states that given [[triangle]] <math>\triangle ABC</math> and [[angle bisector]] AX, where X is on side BC,  then <math>AC/CX = AB/BX</math>.
 
The '''Angle Bisector Theorem''' states that given [[triangle]] <math>\triangle ABC</math> and [[angle bisector]] AX, where X is on side BC,  then <math>AC/CX = AB/BX</math>.
 +
 +
<center>[[Image:Anglebisector.png]]</center>
 +
 +
{{stub}}

Revision as of 15:31, 24 June 2006

The Angle Bisector Theorem states that given triangle $\triangle ABC$ and angle bisector AX, where X is on side BC, then $AC/CX = AB/BX$.

Anglebisector.png

This article is a stub. Help us out by expanding it.