Difference between revisions of "AoPS Wiki:Problem of the Day/June 4, 2011"

Revision as of 22:24, 3 June 2011

Find $x$ where $0<x<1$ such that $10*\{x\}^2+\frac{\lfloor x \rfloor}{\lceil x\rceil}=\frac{9}{10}$

Revision as of 21:54, 3 June 2011 (view source) Btilm305 (talk \| contribs) m (Protected "AoPSWiki:Problem of the Day/June 4, 2011": Problem of the day ([edit=sysop] (indefinite) [move=sysop] (indefinite))) ← Older edit		Revision as of 22:24, 3 June 2011 (view source) Btilm305 (talk \| contribs) (simplified problem) Newer edit →
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−	~~<math>{x}</math> is defined by the smallest positive decimal such that when subtracted from~~ <math>x</math>~~, you get an integer, and~~ <math>0<\{x\}<1~~</math>~~	+	Find <math>x</math> where <math>0<x<1</math> such that <math>10*\{x\}^2+\frac{\lfloor x \rfloor}{\lceil x\rceil}=\frac{9}{10}</math><noinclude>[[category:Problem of the Day]]</noinclude>
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−	~~Find <math>x~~</math> such that <math>10*\{x\}^2+\frac{\lfloor x \rfloor}{\lceil x\rceil}=\frac{9}{10}</math><noinclude>[[category:Problem of the Day]]</noinclude>