Difference between revisions of "AoPS Wiki:Problem of the Day/September 10, 2011"

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==Problem==
 
 
Let <math>F_0 = 0</math>, <math>F_1 = 1</math>, and <math>F_n = F_{n - 1} + F_{n - 2}</math>.  Find the value of the infinite sum <cmath>\sum_{n=1}^{\infty}\frac{F_n}{3^n}=\frac{1}{3} + \frac{1}{9} + \frac{2}{27} + \cdots + \frac{F_n}{3^n} + \cdots.</cmath>
 
Let <math>F_0 = 0</math>, <math>F_1 = 1</math>, and <math>F_n = F_{n - 1} + F_{n - 2}</math>.  Find the value of the infinite sum <cmath>\sum_{n=1}^{\infty}\frac{F_n}{3^n}=\frac{1}{3} + \frac{1}{9} + \frac{2}{27} + \cdots + \frac{F_n}{3^n} + \cdots.</cmath>
==Solution==
 
The solution to this problem can be found [[AoPSWiki talk:Problem of the Day/September 10, 2011|here]] or by clicking [[AoPSWiki talk:Problem of the Day/September 10, 2011|Discussion]] under "Page Tools" at left.
 
 
<noinclude>[[category:Problem of the Day]]</noinclude>
 
<noinclude>[[category:Problem of the Day]]</noinclude>

Revision as of 08:48, 10 September 2011

Let $F_0 = 0$, $F_1 = 1$, and $F_n = F_{n - 1} + F_{n - 2}$. Find the value of the infinite sum \[\sum_{n=1}^{\infty}\frac{F_n}{3^n}=\frac{1}{3} + \frac{1}{9} + \frac{2}{27} + \cdots + \frac{F_n}{3^n} + \cdots.\]