Difference between revisions of "AoPS Wiki talk:Problem of the Day/July 21, 2011"

(Solution)
m (Solution)
Line 2: Line 2:
 
{{:AoPSWiki:Problem of the Day/July 21, 2011}}
 
{{:AoPSWiki:Problem of the Day/July 21, 2011}}
 
==Solution==
 
==Solution==
Note: someone check my arithmetic please
+
Note: someone check the arithmetic please
  
 
For purposes of generalization, let the equations be <math>ax+by=1002001</math> and <math>cx+dy=2004002</math>. Notice that <math>2*1002001 = 2004002</math>. Swap this out for a new variable <math>z</math>.  
 
For purposes of generalization, let the equations be <math>ax+by=1002001</math> and <math>cx+dy=2004002</math>. Notice that <math>2*1002001 = 2004002</math>. Swap this out for a new variable <math>z</math>.  

Revision as of 15:57, 21 July 2011

Problem

AoPSWiki:Problem of the Day/July 21, 2011

Solution

Note: someone check the arithmetic please

For purposes of generalization, let the equations be $ax+by=1002001$ and $cx+dy=2004002$. Notice that $2*1002001 = 2004002$. Swap this out for a new variable $z$. This gives $ax+by=z, cx+dy=2z$.

Multiply the left equation by two and substitute it into the other equation.

$2ax+2by=cx+dy$, which implies that$(c-2a)x=(2b-d)y$. Substituting the actual numbers back in gives: $(997997-686686)x=(630630-8008)y$ Simplifying: $311311x=622722y$ Which further simplifies to: $x=2y$

Therefore:

Sample solution: $x=2, y=1$

General Solution: $x=2n, y=n$