Difference between revisions of "AoPS Wiki talk:Problem of the Day/July 5, 2011"
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==Solution== | ==Solution== | ||
− | {{ | + | Try the only possible integer roots which are <math>\pm</math> {1,2,3,6,7,14,21,42} |
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+ | 3 works so divide out (x-3) to get <math>x^2 + 3x + 14</math> | ||
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+ | Use the quadratic formula to find the remaining roots to be <math>\frac{-3 \pm i\sqrt{47}}{2}</math> | ||
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+ | So, the answers are: <math> \boxed {3; \frac{-3 \pm i\sqrt{47}}{2}} </math>. |
Latest revision as of 15:48, 5 July 2011
Problem
AoPSWiki:Problem of the Day/July 5, 2011
Solution
Try the only possible integer roots which are {1,2,3,6,7,14,21,42}
3 works so divide out (x-3) to get
Use the quadratic formula to find the remaining roots to be
So, the answers are: .