Difference between revisions of "AoPS Wiki talk:Problem of the Day/July 6, 2011"

(Solution)
(Solution)
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<math> n \le 9 </math>: <math>\boxed {123 ... n} </math>
 
<math> n \le 9 </math>: <math>\boxed {123 ... n} </math>
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"Solution"
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<math> 1+11+\cdots+\underbrace{111\cdots 111}_{n}} = n + 10(n-1) + 100(n-2) + \cdots + 10^{n-1}(n-(n-1)</math>. This can be expressed as the summation:
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<math>\boxed{\sum\limits_{k=0}^n 10^{k}(n-k)}</math>

Revision as of 15:00, 6 July 2011

Problem

AoPSWiki:Problem of the Day/July 6, 2011

Solution

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Trivial Case

$n \le 9$: $\boxed {123 ... n}$

"Solution"

$1+11+\cdots+\underbrace{111\cdots 111}_{n}} = n + 10(n-1) + 100(n-2) + \cdots + 10^{n-1}(n-(n-1)$ (Error compiling LaTeX. Unknown error_msg). This can be expressed as the summation:

$\boxed{\sum\limits_{k=0}^n 10^{k}(n-k)}$