Difference between revisions of "AoPS Wiki talk:Problem of the Day/June 13, 2011"

Latest revision as of 21:02, 12 June 2011

First, we can simplify the fraction on the right side of the equation by subtracting the exponents of both numbers.

${\dfrac{2^{3x+7}}{2^{x-1}}=2^{(3x+7)-(x-1)}=2^{2x+8}$ (Error compiling LaTeX. Unknown error_msg)

$8=2^3$ Thus, we add 3 to the exponent.

$2^{x+5}=2^{2x+11}$

Then, we can divide both sides by the left side.

$1=2^{(2x+11)-(x+5)}=2^{x+6}$

$1=2^0$ Therefore,

$0=x+6$

$x=\boxed{-6}$

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 {{:AoPSWiki:Problem of the Day/June 13, 2011}}
 ==Solution==
-{{potd_solution}}
 First, we can simplify the fraction on the right side of the equation by subtracting the exponents of both numbers.