Difference between revisions of "AoPS Wiki talk:Problem of the Day/June 29, 2011"
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This makes the equation (ab+1)(ab+1+a+b)+ab | This makes the equation (ab+1)(ab+1+a+b)+ab | ||
| − | Now we seperate the equation to (ab+1)(ab+1)+(ab+1)(a+b)+ab | + | Now we seperate the equation to <math>(ab+1)(ab+1)+(ab+1)(a+b)+ab</math> |
We get (ab+1)^2 +(a+b)(ab+1)+ab | We get (ab+1)^2 +(a+b)(ab+1)+ab | ||
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Thus we get a factored form of: | Thus we get a factored form of: | ||
| − | (ab+1+a)(ab+1+b) | + | <math>(ab+1+a)(ab+1+b)</math> |
That is the solution | That is the solution | ||
Revision as of 23:08, 28 June 2011
Problem
AoPSWiki:Problem of the Day/June 29, 2011
Solution
This Problem of the Day needs a solution. If you have a solution for it, please help us out by adding it.
First we have the question: (ab+1)(a+1)(b+1)+ab
We multiply (a+1)(b+1) to get (ab+1+a+b)
This makes the equation (ab+1)(ab+1+a+b)+ab
Now we seperate the equation to 
We get (ab+1)^2 +(a+b)(ab+1)+ab
Now this is just a quadratic equation
Thus we get a factored form of:
That is the solution
