Difference between revisions of "AoPS Wiki talk:Problem of the Day/June 29, 2011"

(Solution)
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Thus we get a factored form of:
 
Thus we get a factored form of:
  
<math>(ab+1+a)(ab+1+b)</math>
+
<math>\boxed{(ab+1+a)(ab+1+b)}</math>
 
 
That is the solution
 
 
 
--[[User:Yao95|Yao95]] 23:10, 28 June 2011 (EDT)
 

Revision as of 03:33, 29 June 2011

Problem

AoPSWiki:Problem of the Day/June 29, 2011

Solution

This Problem of the Day needs a solution. If you have a solution for it, please help us out by adding it.


First we have the question: $(ab+1)(a+1)(b+1)+ab$

We multiply $(a+1)(b+1)$ to get $(ab+1+a+b)$

This makes the equation $(ab+1)(ab+1+a+b)+ab$

Now we seperate the equation to $(ab+1)(ab+1)+(ab+1)(a+b)+ab$

We get $(ab+1)^2 +(a+b)(ab+1)+ab$

Now this is just a quadratic equation

Thus we get a factored form of:

$\boxed{(ab+1+a)(ab+1+b)}$