Difference between revisions of "AoPS Wiki talk:Problem of the Day/June 8, 2011"

(Solution)
 
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{{:AoPSWiki:Problem of the Day/June 8, 2011}}
 
{{:AoPSWiki:Problem of the Day/June 8, 2011}}
 
==Solution==
 
==Solution==
<math>12112</math> can be divided into <math>121\times1001</math>
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<math>121121</math> can be divided into <math>121\times1001</math>
  
 
<math>121=11^2</math>
 
<math>121=11^2</math>
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<math>121121=7\times\111^3\times13</math>
 
<math>121121=7\times\111^3\times13</math>
  
<math>7+3(11)+13=\boxed{53}</math>
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<math>(7+1)(11^3+11^2+11+1)(13+1)</math> gives the sum of the factors (expand it and see). Thus, the answer is <math>\boxed{163968}</math>.

Latest revision as of 20:46, 7 June 2011

Problem

AoPSWiki:Problem of the Day/June 8, 2011

Solution

$121121$ can be divided into $121\times1001$

$121=11^2$

$1001=7\times11\times13$

$121121=7\times\111^3\times13$ (Error compiling LaTeX. Unknown error_msg)

$(7+1)(11^3+11^2+11+1)(13+1)$ gives the sum of the factors (expand it and see). Thus, the answer is $\boxed{163968}$.