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Revision history of "AoPS Wiki talk:Problem of the Day/September 17, 2011"

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  • (cur | prev) 06:55, 17 September 2011‎ Negativebplusorminus (talk | contribs)‎ . . (211 bytes) (+211)‎ . . (Created page with "We know that <cmath>(999+1)^3=999^3+3(999)^2+3(999)+1</cmath> by the Binomial Theorem. Since our given expression is one less than that, we compute <cmath>(999+1)^3-1=1,000,000,...")
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