Difference between revisions of "AoPS Wiki talk:Problem of the Day/September 21, 2011"
(Created page with "We see, after substitution, that <cmath>x=\sqrt{x}-2</cmath> and thus, isolating the square root and squaring, <cmath>x=(x+2)^2=x^2+4x+4</cmath> and therefore <math>x^2+3x+4=0</m...") |
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Revision as of 17:54, 21 September 2011
We see, after substitution, that and thus, isolating the square root and squaring, and therefore . The sum of the roots of this equation, by Vieta's formulas, are .