Difference between revisions of "Chebyshev theta function"

(definition and a few properties)
 
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'''Chebyshev's theta function''', denoted <math>\vartheta</math> or sometimes
 
'''Chebyshev's theta function''', denoted <math>\vartheta</math> or sometimes
 
<math>\theta</math>, is a function of use in [[analytic number theory]].
 
<math>\theta</math>, is a function of use in [[analytic number theory]].
It is defined, thus, for real <math>x</math>:
+
It is defined thus, for real <math>x</math>:
 
<cmath> \vartheta(x) = \sum_{p \le x} \log x , </cmath>
 
<cmath> \vartheta(x) = \sum_{p \le x} \log x , </cmath>
 
where the sum ranges over all [[prime number | primes]] less than
 
where the sum ranges over all [[prime number | primes]] less than

Revision as of 15:17, 29 March 2009

Chebyshev's theta function, denoted $\vartheta$ or sometimes $\theta$, is a function of use in analytic number theory. It is defined thus, for real $x$: \[\vartheta(x) = \sum_{p \le x} \log x ,\] where the sum ranges over all primes less than $x$.

Estimates of the function

The function $\vartheta(x)$ is asymptotically equivalent to $\pi(x)$ (the prime counting function) and $x$. This result is the Prime Number Theorem, and all known proofs are rather involved.

However, we can obtain a simpler bound on $\vartheta(x)$.

Theorem (Chebyshev). If $x \ge 0$, then $\vartheta(x) \le 2x$.

Proof. We induct on $\lfloor x \rfloor$. For our base cases, we note that for $0 \le x < 2$, we have $\vartheta(x) = 0 \le x$.

Now suppose that $x \ge 2$. Let $n = \lfloor x \rfloor$. Then \[2^x \ge 2^n \ge \binom{n}{\lfloor n/2 \rfloor} \ge \prod_{\lfloor n/2 \rfloor < p \le n} p ,\] so \[x \ge x \log 2 \ge \sum_{\lfloor n/2 \rfloor < p \le n} \log p = \vartheta{x} - \vartheta{\lfloor n/2 \rfloor} \ge \vartheta{x} - 2\lfloor n/2 \rfloor \ge \vartheta{x} - x ,\] by inductive hypothesis. Therefore \[2x \ge \vartheta(x),\] as desired. $\blacksquare$

See also