Difference between revisions of "Computability and complexity"

 
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== P ==
 
== P ==
Within P, the computational complexity of problems is defined based on the highest degree term in the polynomial <math>P(n)</math>, and is represented using Big-Oh notation.  For example if <math>P(n)</math> has degree <math>5</math>, then <math>P(n) \in O(n^5)</math>.  More formally, if <math>f(x) \in O(g(x)</math>, then <math>\exists C \in \mathbb{R}</math> such that <math>|f(x)| <= C|g(x)|</math> as <math>x -> a</math>, for some <math>a</math> being specified.  Thus, <math>f(x)</math> is bounded by <math>g(x)</math>.
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Within P, the computational complexity of problems is defined based on the highest degree term in the polynomial <math>P(n)</math>, and is represented using Big-Oh notation.  For example if <math>P(n)</math> has degree <math>5</math>, then <math>P(n) \in O(n^5)</math>.  More formally, if <math>f(x) \in O(g(x))</math>, then <math>\exists C \in \mathbb{R}</math> such that <math>|f(x)| <= C|g(x)|</math> as <math>x -> a</math>, for some <math>a</math> being specified.  Thus, <math>f(x)</math> is bounded by <math>g(x)</math>.
 
 
  
 
== NP ==
 
== NP ==
 
NP problems take longer to solve and are not bounded by any polynomial.  Examples include <math>f(n) \in O(2^n)</math>.  A subset of NP problems are NP complete problems.  They have the special property that the rearrangement of any one of them can yield another NP problem.  Thus, if a polynomial time algorithm is found for any NP complete problem, then the conclusion will be that all NP problems are actually P problems, and therefore P = NP.  This is currently one of the Millenium problems for which The Clay Mathematics Institute is offering a $1 million prize for a solution.
 
NP problems take longer to solve and are not bounded by any polynomial.  Examples include <math>f(n) \in O(2^n)</math>.  A subset of NP problems are NP complete problems.  They have the special property that the rearrangement of any one of them can yield another NP problem.  Thus, if a polynomial time algorithm is found for any NP complete problem, then the conclusion will be that all NP problems are actually P problems, and therefore P = NP.  This is currently one of the Millenium problems for which The Clay Mathematics Institute is offering a $1 million prize for a solution.

Revision as of 23:27, 6 January 2007

Classes

Computability is divided into 2 compelxity classes, namely P and NP. For all problems in the P class, there exists a known algorithm to solve the problem in a reasonable amount of time. By this, it is meant that the algorithm will terminate within the time given by some polynomial $P(n)$, where $n$ is the number of elements in the set being examined. In contrast, if a problem is NP, then there is no known algorithm to solve it in a reasonable amount of time.


P

Within P, the computational complexity of problems is defined based on the highest degree term in the polynomial $P(n)$, and is represented using Big-Oh notation. For example if $P(n)$ has degree $5$, then $P(n) \in O(n^5)$. More formally, if $f(x) \in O(g(x))$, then $\exists C \in \mathbb{R}$ such that $|f(x)| <= C|g(x)|$ as $x -> a$, for some $a$ being specified. Thus, $f(x)$ is bounded by $g(x)$.

NP

NP problems take longer to solve and are not bounded by any polynomial. Examples include $f(n) \in O(2^n)$. A subset of NP problems are NP complete problems. They have the special property that the rearrangement of any one of them can yield another NP problem. Thus, if a polynomial time algorithm is found for any NP complete problem, then the conclusion will be that all NP problems are actually P problems, and therefore P = NP. This is currently one of the Millenium problems for which The Clay Mathematics Institute is offering a $1 million prize for a solution.