Difference between revisions of "Derived series"

m (typo)
(added note about nilpotency)
 
Line 4: Line 4:
  
 
A group <math>G</math> for which <math>D^n(G)</math> is [[trivial group |trivial]] for sufficiently large <math>n</math> is called [[solvable group |solvable]].  The least <math>n</math> such that <math>D^n(G) = \{ e\}</math> is called the ''solvability class'' of <math>G</math>.  By transfinite recursion, this notion can be extended to infinite ordinals, as well.
 
A group <math>G</math> for which <math>D^n(G)</math> is [[trivial group |trivial]] for sufficiently large <math>n</math> is called [[solvable group |solvable]].  The least <math>n</math> such that <math>D^n(G) = \{ e\}</math> is called the ''solvability class'' of <math>G</math>.  By transfinite recursion, this notion can be extended to infinite ordinals, as well.
 +
 +
Let <math>C^k(G)</math> be the <math>k</math>th term of the [[lower central series]] of <math>G</math>.  Then from the relation <math>(C^m(G),C^n(G)) \subseteq C^{m+n}(G)</math> and induction, we have
 +
<cmath> D^n(G) \subseteq C^{2^n}(G). </cmath>
 +
In particular, if <math>G</math> is [[nilpotent group |nilpotent]] of class at most <math>2^n-1</math>, then it is solvable of class at most <math>n</math>.  Thus if <math>G</math> is nilpotent, then it is solvable; however, the converse is not generally true.
  
 
By induction on <math>n</math> it follows that if <math>G</math> and <math>G'</math> are groups and <math>f : G \to G'</math> is a [[homomorphism]], then <math>f(D^n(G)) = D^n(f(G)) \subseteq D^n(G')</math>; in particular, if <math>f</math> is [[surjective]], <math>f(D^n(G)) = D^n(G')</math>.  It follows that for all nonnegative integers <math>n</math>, <math>D^n(G)</math> is a [[characteristic subgroup]] of <math>G</math>.
 
By induction on <math>n</math> it follows that if <math>G</math> and <math>G'</math> are groups and <math>f : G \to G'</math> is a [[homomorphism]], then <math>f(D^n(G)) = D^n(f(G)) \subseteq D^n(G')</math>; in particular, if <math>f</math> is [[surjective]], <math>f(D^n(G)) = D^n(G')</math>.  It follows that for all nonnegative integers <math>n</math>, <math>D^n(G)</math> is a [[characteristic subgroup]] of <math>G</math>.

Latest revision as of 01:13, 2 June 2008

The derived series is a particular sequence of decreasing subgroups of a group $G$.

Specifically, let $G$ be a group. The derived series is a sequence $(D^n(G))_{n \ge 0}$ defined recursively as $D^0(G)=G$, $D^{n+1}(G) = D(D^n(G))$, where $D(H)$ is the derived group (i.e., the commutator subgroup) of a group $H$.

A group $G$ for which $D^n(G)$ is trivial for sufficiently large $n$ is called solvable. The least $n$ such that $D^n(G) = \{ e\}$ is called the solvability class of $G$. By transfinite recursion, this notion can be extended to infinite ordinals, as well.

Let $C^k(G)$ be the $k$th term of the lower central series of $G$. Then from the relation $(C^m(G),C^n(G)) \subseteq C^{m+n}(G)$ and induction, we have \[D^n(G) \subseteq C^{2^n}(G).\] In particular, if $G$ is nilpotent of class at most $2^n-1$, then it is solvable of class at most $n$. Thus if $G$ is nilpotent, then it is solvable; however, the converse is not generally true.

By induction on $n$ it follows that if $G$ and $G'$ are groups and $f : G \to G'$ is a homomorphism, then $f(D^n(G)) = D^n(f(G)) \subseteq D^n(G')$; in particular, if $f$ is surjective, $f(D^n(G)) = D^n(G')$. It follows that for all nonnegative integers $n$, $D^n(G)$ is a characteristic subgroup of $G$.

If $G=G_0, G_1, \dotsc$ is a decreasing sequence of subgroups such that $G_{k+1}$ is a normal subgroup of $G_k$ and $G_k/G_{k+1}$ is abelian for all integers $k$, then $D^k(G) \subseteq G_k$, by induction on $k$.

See also