Difference between revisions of "FOIL"

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<cmath>(a+b)(c+d) = ac + ad + bc + bd</cmath>
 
<cmath>(a+b)(c+d) = ac + ad + bc + bd</cmath>
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Here are a few examples.
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<cmath>(5x + 3)(2x - 6)</cmath>
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First we multiply the first terms, <cmath>5x</cmath> and <cmath>2x</cmath>, yielding <cmath>10x^2</cmath>.
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Then, the outside terms, <cmath>5x</cmath> and <cmath>-6</cmath>, giving us <cmath>-30x</cmath>.
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Next, the inside terms, <cmath>3</cmath> and <cmath>2x</cmath>, which is <cmath>6x</cmath>.
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Finally, we multiply the last terms, <cmath>-6</cmath> and <cmath>3</cmath>, which is <cmath>-18</cmath>.
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Thus, our answer is <cmath>10x^2 - 30x + 6x - 18</cmath>, which, when simplified, gives us a final answer of <cmath>\boxed{10x^2 - 24x - 18}</cmath>.
  
 
== See also ==
 
== See also ==

Revision as of 12:00, 16 August 2008

FOIL, standing for first, outside, inside, last, is a mnemonic device for remembering the distributive property when two binomials are multiplied.

\[(a+b)(c+d) = ac + ad + bc + bd\]

Here are a few examples.

\[(5x + 3)(2x - 6)\]

First we multiply the first terms, \[5x\] and \[2x\], yielding \[10x^2\].

Then, the outside terms, \[5x\] and \[-6\], giving us \[-30x\].

Next, the inside terms, \[3\] and \[2x\], which is \[6x\].

Finally, we multiply the last terms, \[-6\] and \[3\], which is \[-18\].

Thus, our answer is \[10x^2 - 30x + 6x - 18\], which, when simplified, gives us a final answer of \[\boxed{10x^2 - 24x - 18}\].

See also

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