Difference between revisions of "Law of Sines"

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Revision as of 23:21, 22 June 2006

Given a triangle with side lengths a, b, and c, opposite angles A, B, and C, and a circumcircle with radius R, $\frac{a}{\sin{A}}=\frac{b}{\sin{B}}=\frac{c}{\sin{C}}=2R$.