Difference between revisions of "Mock AIME 1 Pre 2005 Problems/Problem 9"
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385 & = (p - 1)(q - 1)(r - 1) \\ | 385 & = (p - 1)(q - 1)(r - 1) \\ | ||
\end{align*}</cmath> | \end{align*}</cmath> | ||
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From here, you can factor <math>385</math> as <math>5 \cdot 7 \cdot 11</math>, giving corresponding values of <math>6, 8,</math> and <math>12</math>. The answer is <math>6 \cdot 8 \cdot 12=576</math>. | From here, you can factor <math>385</math> as <math>5 \cdot 7 \cdot 11</math>, giving corresponding values of <math>6, 8,</math> and <math>12</math>. The answer is <math>6 \cdot 8 \cdot 12=576</math>. | ||
Latest revision as of 21:47, 21 February 2010
Problem
and are three non-zero integers such that and Compute .
Solution
From here, you can factor as , giving corresponding values of and . The answer is .
See also
Mock AIME 1 Pre 2005 (Problems, Source) | ||
Preceded by Problem 8 |
Followed by Problem 10 | |
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15 |