Difference between revisions of "Mock AIME 2 2006-2007 Problems/Problem 11"

Revision as of 13:19, 8 October 2007

Problem

Find the sum of the squares of the roots, real or complex, of the system of simultaneous equations

$x+y+z=3,~x^2+y^2+z^2=3,~x^3+y^3+z^3 =3.$

Solution

The sums of the squares of the roots is given in the problem; 3.

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Mock AIME 2 2006-2007

Problem Source

This problem was given to 4everwise by a friend, Henry Tung. Upper classmen bullying freshmen. (Just kidding; it's a nice problem. ) This problem is also incredibly similar to 1973 USAMO problem 4.

@@ Line 5: / Line 5: @@
 ==Solution==
-We take note of the obvious solution: (1,1,1). Now we manipulate the equations a bit:
+The sums of the squares of the roots is given in the problem; 3.
-<math>(x+y+z)^2-(x^2+y^2+z^2)=2xy+2xz+2yz=6</math>
-<math>(x+y+z)(x^2+y^2+z^2)=x^3+y^3+z^3+x^2(y+z)+y^2(x+z)+z^2(y+x)=9=3+x^2(y+z)+y^2(x+z)+z^2(y+x)</math>
-<math>(x+y+z)^3=x^3+y^3+z^3+3(x^2(y+z)+y^2(x+z)+z^2(y+x))+6xyz=3+18+6xyz=27</math>
-<math>x+y+z=3</math>
-<math>xy+xz+zy=3</math>
-<math>xyz=1</math>
-Therefore, x, y, and z are the roots of
-<math>a^3-3a^2+3a-1=(a-1)^3</math>
-Therefore, the only solution to those three equations is (1,1,1). The sum of the squares of the roots is <math>1^2+1^2+1^2=3</math>
@@ Line 42: / Line 16: @@
 *[[Mock AIME 2 2006-2007]]
 == Problem Source==
 This problem was given to 4everwise by a friend, Henry Tung. Upper classmen bullying freshmen. (Just kidding; it's a nice problem. [[Image:Razz.gif]]) This problem is also incredibly similar to 1973 USAMO problem 4.

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Difference between revisions of "Mock AIME 2 2006-2007 Problems/Problem 11"

Revision as of 13:19, 8 October 2007

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