Difference between revisions of "Mock AIME 5 Pre 2005 Problems/Problem 12"

Revision as of 16:53, 18 August 2013

Let $m = 101^4 + 256$ . Find the sum of the digits of $m$ .

By the binomial theorem, $101^4 + 256 = 104060401 + 256 = 104060657$ , and $s(m) = \boxed{029}$ .

@@ Line 1: / Line 1: @@
 == Problem ==
-Let <math>m = 101^4 + 256</math>. Find the sum of digits of <math>m</math>.
+Let <math>m = 101^4 + 256</math>. Find the sum of the digits of <math>m</math>.
 == Solution ==

Mock AIME 5 Pre 2005 (Problems, Source)
Preceded by Problem 11	Followed by Problem 13
1 • 2 • 3 • 4 • 5 • 6 • 7 • 8 • 9 • 10 • 11 • 12 • 13 • 14 • 15