Difference between revisions of "Polynomial Remainder Theorem"

(Created page with "==Statement== The Polynomial Remainder Theorem states that for <math>\frac{f(x)}{x-a}</math> the remainder is <math>f(a)</math> ==Proof== Assuming <math>r</math>=re...")
 
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==Proof==
 
==Proof==
  
Assuming <math>r</math>=remainder <math>q(x)</math>=quotient and <math>f(x)</math> as a polynomial:
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Assuming <math>r</math> = remainder <math>q(x)</math> = quotient and <math>f(x)</math> as a polynomial:
  
 
<math>f(x)=q(x)(x-a)+r</math>
 
<math>f(x)=q(x)(x-a)+r</math>

Revision as of 20:36, 12 February 2018

Statement

The Polynomial Remainder Theorem states that for $\frac{f(x)}{x-a}$ the remainder is $f(a)$

Proof

Assuming $r$ = remainder $q(x)$ = quotient and $f(x)$ as a polynomial:

$f(x)=q(x)(x-a)+r$

If we plug in $a$ into the polynomial $f(x)$ and $x-a$ (Do not plug $a$ into $q(x)$. Assume $q(x)$ as only a variable for quotient) we get:

$f(a)=r$