Difference between revisions of "Regular tetrahedron/Introductory problem"

(New page: ==Problem== Find the volume of a tetrahedron whose sides all have length <math>2</math>. ==Solution== We find the area of the base: <math>\mathrm {A} =\dfrac{4\sqrt{3}}{4}=\sqrt...)
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Revision as of 13:53, 23 September 2007

Problem

Find the volume of a tetrahedron whose sides all have length $2$.

Solution

We find the area of the base:

$\mathrm {A} =\dfrac{4\sqrt{3}}{4}=\sqrt{3}$

Now we find the lateral height:

$\mathrm {lh}=\sqrt{2^2-1^2}=\sqrt{3}$

Now we can find the height of the tetrahedron:

$\mathrm {h}=\sqrt{\sqrt{3})^2-(\dfrac{1}{3}*\sqrt{3})^2}=\sqrt{\dfrac{8}{3}$ (Error compiling LaTeX. Unknown error_msg)

Now the volume of the tetrahedron is:

$\dfrac{1}{3}*\sqrt{3}*\sqrt{\dfrac{8}{3}}=\dfrac{\sqrt{8}}{3}$


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