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• | 292 || Quacker88 || 6 || 4445.787 || 740.965
187 KB (10,824 words) - 03:10, 29 December 2021
• ~quacker88
5 KB (676 words) - 15:40, 6 November 2021
• ...he triangle is $\frac{4}{3}\cdot{72}=\boxed{\textbf{(C) } 96}$ ~quacker88, diagram by programjames1 ~quacker88
9 KB (1,347 words) - 22:14, 1 May 2021
• ~quacker88 ($\LaTeX$ Adjustments)
1 KB (200 words) - 12:41, 27 August 2021
• ...d line segments. The sum is $\boxed{\textbf{C) }13+4\sqrt{2}}$ ~quacker88
2 KB (259 words) - 20:21, 24 March 2021
• ~quacker88 (Solution)
5 KB (699 words) - 05:02, 3 January 2022
• ~quacker88
1 KB (182 words) - 16:18, 27 August 2021
• $4A\equiv8\pmod{9} \implies A=\boxed{\textbf{(A) }2}$ ~quacker88
5 KB (739 words) - 18:25, 7 November 2021
• $5+40=\boxed{\textbf{(E) }45}$ ~quacker88
2 KB (313 words) - 01:08, 5 January 2021
• ...hich IS prime, so we have our answer $\boxed{\textbf{(D)}\ 7}$ ~quacker88
2 KB (325 words) - 17:21, 18 May 2021
• ~quacker88 ~quacker88
3 KB (523 words) - 02:16, 26 August 2021
• ...frac{1}{15}+\frac{1}{15}+\frac{1}{15}=\boxed{\textbf{(B) }\frac15}[/itex] ~quacker88
10 KB (1,641 words) - 18:20, 7 November 2021
• ...hown earlier, the remainder must be $\boxed{\textbf{(D) }201}$ ~quacker88
3 KB (392 words) - 19:43, 31 October 2021
• ~quacker88
2 KB (356 words) - 18:29, 6 September 2021
• ...urs, she drove at $\frac{110}{2}=\boxed{\textbf{(B) }55}$ mph. ~quacker88
1 KB (218 words) - 16:20, 6 April 2021
• $\frac{10\cdot10}{252}=\boxed{\textbf{(D) }\frac{25}{63}}$ ~quacker88
3 KB (405 words) - 16:59, 6 April 2021
• ~quacker88
6 KB (1,011 words) - 12:57, 23 July 2020