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File:Triangle area ratio lemma.jpg ...and $F$ are on $AB, BC, AC$ such that $AD:DB=1:a, BE:EC=1:b$ and $FC:FA=1:c$ Then $[DEF]=\left|\frac{[ABC](1+abc)}{(1+a)(1+b)(1+c)}\right|$(658 × 602 (22 KB)) - 04:56, 19 May 2024