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• 1991 AIME Problems/Problem 6
  ...e there are 19 terms in the former equation and 8 terms in the latter, our anser is <math>\lfloor nx\rfloor = 546+19\cdot 7+8\cdot 8=\boxed{743}</math>
  3 KB (432 words) - 10:23, 1 October 2020
• 2005 AMC 10B Problems/Problem 25
  ...>. When we solve for <math>n</math>, we get <math>n = 62</math>. Thus, the anser is <math>\boxed{\mathrm{(C)}\ 62}</math>.
  3 KB (401 words) - 11:50, 10 January 2021
• 2010 AIME I Problems/Problem 13
  ...{27}}=21 \cdot 63 \sqrt{3},</math> so <math>a = 63 \sqrt{6}</math> and the anser is <math>\boxed{069}.</math>
  9 KB (1,325 words) - 11:30, 15 July 2020