Difference between revisions of "Talk:1983 AIME Problems/Problem 3"
(New page: I think what the first solution meant to say is that <math>y=-6</math> is an extraneous solution since <math>-6 \neq 2\sqrt{-6+15}</math> (the <math>\sqrt{}</math> symbol is defined as the...) |
(No difference)
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Revision as of 21:49, 21 May 2009
I think what the first solution meant to say is that 
is an extraneous solution since 
(the 
symbol is defined as the positive square root.) Thus, solution one has the correct answer.
