Difference between revisions of "Talk:2000 AIME I Problems/Problem 12"
Silversheep (talk | contribs) (New page: The explanation is unclear. I got the answer 352/2=176. From f(x)=f(x+352) all x with same residue mod 352 give the same answer. Additionally pairs (x,y) with x+y=46 mod 352 have same f(x)...) |
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From f(x)=f(x+352) all x with same residue mod 352 give the same answer. | From f(x)=f(x+352) all x with same residue mod 352 give the same answer. | ||
Additionally pairs (x,y) with x+y=46 mod 352 have same f(x). There are 176 such pairs. | Additionally pairs (x,y) with x+y=46 mod 352 have same f(x). There are 176 such pairs. | ||
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| + | :No, I think the explanation is fine. I believe you left out that <math>(x,y) = (23,23),(199,199)</math> don't overlap, which explains the off-by-one. <font style="font-family:Georgia,sans-serif">[[User:Azjps|Azjps]] ([[User talk:Azjps|<font color="green">talk</font>]])</font> 14:57, 29 March 2008 (UTC) | ||
Latest revision as of 10:57, 29 March 2008
The explanation is unclear. I got the answer 352/2=176. From f(x)=f(x+352) all x with same residue mod 352 give the same answer. Additionally pairs (x,y) with x+y=46 mod 352 have same f(x). There are 176 such pairs.
don't overlap, which explains the off-by-one. 
