# Difference between revisions of "Talk:2010 AMC 12B Problems/Problem 25"

(it's an amc problem not a research paper -_-) |
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− | + | Because the AMC has a short time limit, yes, you "just have to cross our fingers and guess". |

## Latest revision as of 00:26, 24 January 2021

How do we know that 67 will yield the smallest result of 77?

I created a Mathematica function to check all primes <= 67, and yes indeed 67 gave the smallest result of 77 but 2 gives a problematically close 78. And the trend is not always decreasing:

x = 2, 3, 5, 7, 11, 13, 17, 19, 23, 29, 31, 37, 41, 43, 47, 53, 59, 61, 67 f(x) = 78, 140, 162, 189, 164, 177, 162, 162, 149, 130, 128, 113, 108, 105, 99, 92, 83, 82, 77

So if the target problem was not but , then 13 as the largest prime in 2001=7*11*13 will give an incorrect answer of . The correct answer will be .

Do we just have to cross our fingers and guess that it is f(67)=77 is indeed the smallest?

--- buhiroshi0205

Because the AMC has a short time limit, yes, you "just have to cross our fingers and guess".