Difference between revisions of "Talk:2013 AIME I Problems/Problem 14"
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For solution 1 where they talk about <math>P \sin \theta + Q \cos \theta = \cos \theta - \frac{1}{2} P</math>, I got <cmath> \cos \theta - \frac{1}{4} \cos \theta + \frac{1}{8} \sin 2 \theta - \frac{1}{16} \cos 3 \theta + \frac{1}{32} \sin 4 \theta - \dots </cmath> instead (the same as in solution 2), which is not what the solution 1 got. If the writer of solution 1 could resolve this, that would be great. | For solution 1 where they talk about <math>P \sin \theta + Q \cos \theta = \cos \theta - \frac{1}{2} P</math>, I got <cmath> \cos \theta - \frac{1}{4} \cos \theta + \frac{1}{8} \sin 2 \theta - \frac{1}{16} \cos 3 \theta + \frac{1}{32} \sin 4 \theta - \dots </cmath> instead (the same as in solution 2), which is not what the solution 1 got. If the writer of solution 1 could resolve this, that would be great. | ||
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Revision as of 13:10, 27 December 2021
For solution 1 where they talk about 
, I got ![\[\cos \theta - \frac{1}{4} \cos \theta + \frac{1}{8} \sin 2 \theta - \frac{1}{16} \cos 3 \theta + \frac{1}{32} \sin 4 \theta - \dots\]](http://latex.artofproblemsolving.com/9/8/6/986b91b073c8e5238d7bac403ff6588753d245ac.png)
instead (the same as in solution 2), which is not what the solution 1 got. If the writer of solution 1 could resolve this, that would be great.
~MeepMurp5
