Difference between revisions of "Talk:2013 AMC 10A Problems/Problem 8"
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Latest revision as of 23:57, 6 February 2013
Can anyone explain why the answer is 15???? I thought that since there are ten 2 person teams possible, there must have been five people total. (5 choose 2= 10) So, since the people could be in multiple committees, the number of 3 person teams would be 5 choose 3 = 10??
