Talk:2022 AIME I Problems/Problem 2
seems the most beautiful answers using modulus and inequality are flawed, and need minor revisions to fit the rigor of math
(modulus) 8c mod 71 can be 1 if c=9 instead of 8c
(inequality) 99(a-b) can be negative, and 4(2c-7b) can have a few negative values to get them equal.
Which solutions are you referring to?
All possible remainders modulo are
Although and are not in the set, it is still true that Recall that the numbers and are congruent modulo if and only if