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The local theater has one ticket window. In how many ways can six people line up to buy a ticket?

Revision as of 16:49, 28 February 2021 by Aaryavseth (talk | contribs) (We must count the number of permutations of 6 people. There are 6 choices for the first person in line, 5 choices for the second person in line, etc. So the answer is $6\cdot5\cdot 4\cdot 3\cdot2\cdot 1=\boxed{720}$.)
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The local theater has one ticket window. In how many ways can six people line up to buy a ticket?

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