Difference between revisions of "University of South Carolina High School Math Contest/1993 Exam/Problem 10"
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If we construct right triangles for each pair of arguments (<math>\arcsin, \arccos</math> and <math>\arctan, \arccot</math>), we see that the sum of the angles is <math>90^\circ+90^\circ=\pi</math>. | If we construct right triangles for each pair of arguments (<math>\arcsin, \arccos</math> and <math>\arctan, \arccot</math>), we see that the sum of the angles is <math>90^\circ+90^\circ=\pi</math>. | ||
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| − | * [[University of South Carolina High School Math Contest/1993 Exam]] | + | |
| + | * [[University of South Carolina High School Math Contest/1993 Exam/Problem 9|Previous Problem]] | ||
| + | * [[University of South Carolina High School Math Contest/1993 Exam/Problem 11|Next Problem]] | ||
| + | * [[University of South Carolina High School Math Contest/1993 Exam|Back to Exam]] | ||
[[Category:Introductory Trigonometry Problems]] | [[Category:Introductory Trigonometry Problems]] | ||
Revision as of 12:24, 23 July 2006
Problem
Arcsin(1/3) + Arccos(1/3) + Arctan(1/3) + Arccot(1/3) =
Solution
If we construct right triangles for each pair of arguments (
and $\arctan, \arccot$ (Error compiling LaTeX. Unknown error_msg)), we see that the sum of the angles is 
.
