Difference between revisions of "University of South Carolina High School Math Contest/1993 Exam/Problem 18"
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which is just <math>\pm 1 \pm 1 \pm 1 \pm 1</math>. The minimum value is thus -4. | which is just <math>\pm 1 \pm 1 \pm 1 \pm 1</math>. The minimum value is thus -4. | ||
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+ | [[Category:Intermediate Trigonometry Problems]] |
Revision as of 12:14, 23 July 2006
Problem
The minimum value of the function
as varies over all numbers in the largest possible domain of , is
Solution
Recall the Pythagorean Identities:
We can now simplify the function to
which is just . The minimum value is thus -4.