Difference between revisions of "University of South Carolina High School Math Contest/1993 Exam/Problem 23"
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Any integer that can be created through <math>M</math> can be created through <math>N</math> and vice versa. Thus <math>M=N</math>. | Any integer that can be created through <math>M</math> can be created through <math>N</math> and vice versa. Thus <math>M=N</math>. | ||
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Revision as of 17:20, 17 August 2006
Problem
The relation between the sets
and
is
Solution
Any integer that can be created through can be created through and vice versa. Thus .
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