Difference between revisions of "User:R31415"

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'''<math>e^ i\pi =-1</math>'''
+
==Awesomeness==
Which means that i^i equals <math>(e^i*e^\pi*e^ 1/2)^i= e^-\pi/2
+
<math>e^ {i\pi}= -1</math>
</math>(e^i*e^\pi*e^1/2)^i= e^-\pi/2$
+
<br><math>i^i = (e^ {i\pi/2})^i = e^ {-\pi/2}</math>
<dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/>
+
 
<br> ah well... LaTeX is hard...
+
<dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/>=

Revision as of 21:22, 7 January 2011

Awesomeness

$e^ {i\pi}= -1$
$i^i = (e^ {i\pi/2})^i = e^ {-\pi/2}$

<dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/><dollar/>=