Difference between revisions of "User:Rusczyk"

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==<font color="white" style="font-family: ITC Avant Garde Gothic Std, Verdana"><div style="margin-left:10px">User Count</div></font>==
 
==<font color="white" style="font-family: ITC Avant Garde Gothic Std, Verdana"><div style="margin-left:10px">User Count</div></font>==
 
<div style="margin-left: 10px; margin-bottom:10px"><font color="white">If this is your first time visiting this page, edit it by incrementing the user count below by one.</font></div><font color="white">
 
<div style="margin-left: 10px; margin-bottom:10px"><font color="white">If this is your first time visiting this page, edit it by incrementing the user count below by one.</font></div><font color="white">
<center><font size="101px"><math>10^{10^{10^{10^{100}}}}</math></font></center>
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<center><font size="101px"><math>10^{100000000000000000000}</math></font></center>
 
</div>
 
</div>
 
<div style="border:2px solid black; background:#4EC284;-webkit-border-radius: 10px; align:center">
 
<div style="border:2px solid black; background:#4EC284;-webkit-border-radius: 10px; align:center">

Revision as of 01:16, 12 September 2020

Rusczyk's Page:

User Count

If this is your first time visiting this page, edit it by incrementing the user count below by one.
$10^{100000000000000000000}$

About Me

Rusczyk is currently borderline AIME.

Rusczyk just turned 13 years old.

Rusczyk scored 44/46 when mocking the 2018 MATHCOUNTS State test, and got silver on the 2020 online MATHCOUNTS State held on AoPS.

Rusczyk is a pro at maths and physics

Rusczyk has come world and country #1 in various international tournaments and competitions starting from 2017

I am better than Rusczyk at math

Goals

A User Count of $\infty$

Make AIME 2021 (Currently borderline)

Pass AP Calculus AB, BC and AP Physics exam

Get in the Alcumus HoF in the next 6 months

Convince OlympusHero that he is better than Rusczyk (at Math)

Get $\color{white}{2 \times}$ medals this year as compared to what they did last year. That is $\color{white}{2 \times 14 = \boxed{28}}$ which is nearly impossible.

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